1v^2-5v+12=0

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Solution for 1v^2-5v+12=0 equation:


Simplifying
1v2 + -5v + 12 = 0

Reorder the terms:
12 + -5v + 1v2 = 0

Solving
12 + -5v + 1v2 = 0

Solving for variable 'v'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + -5v + -12 + v2 = 0 + -12

Reorder the terms:
12 + -12 + -5v + v2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -5v + v2 = 0 + -12
-5v + v2 = 0 + -12

Combine like terms: 0 + -12 = -12
-5v + v2 = -12

The v term is -5v.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5v + 6.25 + v2 = -12 + 6.25

Reorder the terms:
6.25 + -5v + v2 = -12 + 6.25

Combine like terms: -12 + 6.25 = -5.75
6.25 + -5v + v2 = -5.75

Factor a perfect square on the left side:
(v + -2.5)(v + -2.5) = -5.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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